Revision 4937
Added by Aaron Marcuse-Kubitza about 12 years ago
| strings.py | ||
|---|---|---|
| 40 | 40 |
if str_ == '': return [] |
| 41 | 41 |
else: return str_.split(sep) |
| 42 | 42 |
|
| 43 |
def remove_prefix(prefix, str_, removed_ref=None): |
|
| 43 |
def remove_prefix(prefix, str_, removed_ref=None, require=False):
|
|
| 44 | 44 |
if removed_ref == None: removed_ref = [False] |
| 45 | 45 |
|
| 46 | 46 |
removed_ref[0] = str_.startswith(prefix) |
| 47 | 47 |
if removed_ref[0]: return str_[len(prefix):] |
| 48 |
elif require: raise Exception(urepr(str_)+' needs '+urepr(prefix)+' prefix') |
|
| 48 | 49 |
else: return str_ |
| 49 | 50 |
|
| 50 | 51 |
def remove_prefixes(prefixes, str_): |
| ... | ... | |
| 53 | 54 |
|
| 54 | 55 |
def with_prefixes(prefixes, str_): return (p+str_ for p in prefixes) |
| 55 | 56 |
|
| 56 |
def remove_suffix(suffix, str_, removed_ref=None): |
|
| 57 |
def remove_suffix(suffix, str_, removed_ref=None, require=False):
|
|
| 57 | 58 |
if removed_ref == None: removed_ref = [False] |
| 58 | 59 |
|
| 59 | 60 |
removed_ref[0] = str_.endswith(suffix) |
| 60 | 61 |
if removed_ref[0]: return str_[:-len(suffix)] |
| 62 |
elif require: raise Exception(urepr(str_)+' needs '+urepr(suffix)+' suffix') |
|
| 61 | 63 |
else: return str_ |
| 62 | 64 |
|
| 63 | 65 |
def contains_any(haystack, needles): |
Also available in: Unified diff
strings.py: remove_prefix(), remove_suffix(): Added require param to raise aan exception if the string does not have the given prefix/suffix