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Revision 1765

Added by Aaron Marcuse-Kubitza about 12 years ago

maps.py: Added cols_combinable() and use it in combinable(). Added join_combinable() and associates helper functions. Added documentation labels to each section.

View differences:

lib/maps.py
6 6 
import strings
7 7 
import util
8 8 

  		




  
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##### Metadata


  		




  
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def col_info(col_name, require_root=False):


  		




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    '''@return tuple (label, root, prefixes)'''


  		




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    def syntax_err(): raise Parser.SyntaxError('Column name must have '


  		




  ......




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    if require_root and root == None: syntax_err()


  		




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    return label, root, strings.split(',', util.coalesce(prefixes, ''))


  		




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##### Combinability


  		




  
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def col_formats(col_name):


  		




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    label, root, prefixes = col_info(col_name)


  		




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    return [label]+prefixes


  		




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def combinable(*headers):


  		




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    return strings.overlaps(*[','.join(col_formats(h[0])) for h in headers])


  		




  
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def cols_combinable(*col_names):


  		




  
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    return strings.overlaps(*[','.join(col_formats(c)) for c in col_names])


  		




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def combinable(*headers): return cols_combinable(*[h[0] for h in headers])


  		




  
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def strip_root(root): return re.sub(r':\[[^\]]*?\]', r'', root)


  		




  
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def stripped_root(col_name):


  		




  
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    '''@return NamedTuple (labels, root)'''


  		




  
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    label, root = col_info(col_name)[:2]


  		




  
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    return util.do_ignore_none(strip_root, root)


  		




  
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def roots_combinable(*roots):


  		




  
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    roots = map(stripped_root, roots)


  		




  
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    return roots[0] == None or roots[1] == None or roots[0] == roots[1]


  		




  
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def join_combinable(*headers):


  		




  
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    cols = [headers[0][1], headers[1][0]]


  		




  
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    return combinable(*cols) and roots_combinable(*cols)


  		




  
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##### Merging


  		




  
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def is_nonexplicit_empty_mapping(row):


  		




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    return reduce(util.and_, (v == '' for v in row[1:]))


  		




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