Revision 4500
Added by Aaron Marcuse-Kubitza about 12 years ago
| bin/join | ||
|---|---|---|
| 16 | 16 |
import opts |
| 17 | 17 |
import util |
| 18 | 18 |
|
| 19 |
def simplify(str_): return re.sub(r'[\W_]+', r'', str_.lower()) |
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| 20 |
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|
| 21 | 19 |
def main(): |
| 22 | 20 |
env_names = [] |
| 23 | 21 |
def usage_err(): |
| ... | ... | |
| 39 | 37 |
map_1_cols = reader.next() |
| 40 | 38 |
for row in reader: |
| 41 | 39 |
if map_1_core_only: row = row[:2] |
| 42 |
if row[0] != '': map_1.setdefault(simplify(row[0]), []).append(row) |
|
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if row[0] != '': map_1.setdefault(maps.simplify(row[0]), []).append(row)
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|
| 43 | 41 |
stream.close() |
| 44 | 42 |
|
| 45 | 43 |
# Join map 1 to map 0 |
| ... | ... | |
| 66 | 64 |
suffix = '' |
| 67 | 65 |
while True: |
| 68 | 66 |
try: |
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out_rows = map_1[simplify(row[1])] |
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out_rows = map_1[maps.simplify(row[1])]
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|
| 70 | 68 |
break |
| 71 | 69 |
except KeyError: |
| 72 | 70 |
# Heuristically look for a match on a parent path. |
Also available in: Unified diff
join: Use new maps.simplify()