Revision b7b786b1
Added by Adam M. Wilson over 12 years ago
| climate/extra/dailydatasize.r | ||
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## Land Area |
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n.land=148940000 #km2, from http://en.wikipedia.org/wiki/Earth |
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## total values |
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## total values (space x time)
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n.landtime=n.dates*n.land |
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n.globetime=n.dates*n.globe |
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| ... | ... | |
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### approximate storage size for various data types |
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types=as.data.frame(matrix(c( |
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"Short integer",-32768, 32767,2, |
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"Long integer", -2147483648,2147483647,4, |
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"Single-precision floating-point", -3.4e38,1.2e38,4, |
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"Double-precision floating-point", -2.2e308,1.8e308,8 |
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),ncol=4,byrow=T,dimnames=list(1:4,c("type","min","max","bytes"))),stringsAsFactors=F)
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"short int","Short integer",-32768, 32767,2,
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"long int","Long integer", -2147483648,2147483647,4,
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"single","Single-precision floating-point", -3.4e38,1.2e38,4,
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"double","Double-precision floating-point", -2.2e308,1.8e308,8
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),ncol=5,byrow=T,dimnames=list(1:4,c("type","longtype","min","max","bytes"))),stringsAsFactors=F)
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types$min=as.numeric(types$min);types$max=as.numeric(types$max);types$bytes=as.numeric(types$bytes) |
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types |
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### now estimate TB storage for total values (not full grid, just the values)
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### now estimate TB storage for total values |
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types$storage.landtime.TB=n.landtime*types$bytes/2^40
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types$storage.globetime.TB=n.globetime*types$bytes/2^40; types
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types$storage.landtime.TB=round(n.landtime*types$bytes/2^40,1)
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types$storage.globetime.TB=round(n.globetime*types$bytes/2^40,1); types
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types[,-c(2:4)] |
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Also available in: Unified diff
Minor updates to dataset size calculation