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### Brief script to explore the total size of the 1km daily (1970-2010) dataset
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## Time
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dates=seq(as.Date("1970-01-01"),as.Date("2010-01-01"),by=1)
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n.dates=length(dates)
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## Total area
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n.globe=510072000 #km2, from http://en.wikipedia.org/wiki/Earth
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## Land Area
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n.land=148940000 #km2, from http://en.wikipedia.org/wiki/Earth
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## total values (space x time)
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n.landtime=n.dates*n.land
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n.globetime=n.dates*n.globe
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n.landtime
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n.globetime
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formatC(n.landtime, format="f",digits=0, big.mark=',')
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### approximate storage size for various data types
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types=as.data.frame(matrix(c(
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"short int","Short integer",-32768, 32767,2,
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"long int","Long integer", -2147483648,2147483647,4,
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"single","Single-precision floating-point", -3.4e38,1.2e38,4,
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"double","Double-precision floating-point", -2.2e308,1.8e308,8
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),ncol=5,byrow=T,dimnames=list(1:4,c("type","longtype","min","max","bytes"))),stringsAsFactors=F)
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types$min=as.numeric(types$min);types$max=as.numeric(types$max);types$bytes=as.numeric(types$bytes)
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types
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### now estimate TB storage for total values
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types$storage.landtime.TB=round(n.landtime*types$bytes/2^40,1)
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types$storage.globetime.TB=round(n.globetime*types$bytes/2^40,1); types
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types[,-c(2:4)]
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